python如何实现自动扫雷-创新互联
这篇文章主要介绍了python如何实现自动扫雷，具有一定借鉴价值，感兴趣的朋友可以参考下，希望大家阅读完这篇文章之后大有收获，下面让小编带着大家一起了解一下。
前言
自动扫雷一般分为两种，一种是读取内存数据，而另一种是通过分析图片获得数据，并通过模拟鼠标操作，这里我用的是第二种方式。
一、准备工作
1.扫雷游戏
我是win10，没有默认的扫雷，所以去扫雷网下载
http://www.saolei.net/BBS/
2.python 3
我的版本是 python 3.6.1
3.python的第三方库
win32api,win32gui,win32con,Pillow,numpy,opencv
可通过 pip install --upgrade SomePackage 来进行安装
注意：有的版本是下载pywin32，但是有的要把pywin32升级到最高并自动下载了pypiwin32，具体情况每个python版本可能都略有不同
我给出我的第三方库和版本仅供参考
二、关键代码组成
1.找到游戏窗口与坐标
#扫雷游戏窗口
class_name = "TMain"
title_name = "Minesweeper Arbiter "
hwnd = win32gui.FindWindow(class_name, title_name)
#窗口坐标
left = 0
top = 0
right = 0
bottom = 0
if hwnd:
print("找到窗口")
left, top, right, bottom = win32gui.GetWindowRect(hwnd)
#win32gui.SetForegroundWindow(hwnd)
print("窗口坐标：")
print(str(left)+' '+str(right)+' '+str(top)+' '+str(bottom))
else:
print("未找到窗口")2.锁定并抓取雷区图像
#锁定雷区坐标#去除周围功能按钮以及多余的界面#具体的像素值是通过QQ的截图来判断的 left += 15 top += 101 right -= 15 bottom -= 42 #抓取雷区图像 rect = (left, top, right, bottom) img = ImageGrab.grab().crop(rect)
3.各图像的RGBA值
#数字1-8 周围雷数 #0 未被打开 #ed 被打开 空白 #hongqi 红旗 #boom 普通雷#boom_red 踩中的雷 rgba_ed = [(225, (192, 192, 192)), (31, (128, 128, 128))] rgba_hongqi = [(54, (255, 255, 255)), (17, (255, 0, 0)), (109, (192, 192, 192)), (54, (128, 128, 128)), (22, (0, 0, 0))] rgba_0 = [(54, (255, 255, 255)), (148, (192, 192, 192)), (54, (128, 128, 128))] rgba_1 = [(185, (192, 192, 192)), (31, (128, 128, 128)), (40, (0, 0, 255))] rgba_2 = [(160, (192, 192, 192)), (31, (128, 128, 128)), (65, (0, 128, 0))] rgba_3 = [(62, (255, 0, 0)), (163, (192, 192, 192)), (31, (128, 128, 128))] rgba_4 = [(169, (192, 192, 192)), (31, (128, 128, 128)), (56, (0, 0, 128))] rgba_5 = [(70, (128, 0, 0)), (155, (192, 192, 192)), (31, (128, 128, 128))] rgba_6 = [(153, (192, 192, 192)), (31, (128, 128, 128)), (72, (0, 128, 128))] rgba_8 = [(149, (192, 192, 192)), (107, (128, 128, 128))] rgba_boom = [(4, (255, 255, 255)), (144, (192, 192, 192)), (31, (128, 128, 128)), (77, (0, 0, 0))] rgba_boom_red = [(4, (255, 255, 255)), (144, (255, 0, 0)), (31, (128, 128, 128)), (77, (0, 0, 0))]
4.扫描雷区图像保存至一个二维数组map
#扫描雷区图像
def showmap():
img = ImageGrab.grab().crop(rect)
for y in range(blocks_y):
for x in range(blocks_x):
this_image = img.crop((x * block_width, y * block_height, (x + 1) * block_width, (y + 1) * block_height))
if this_image.getcolors() == rgba_0:
map[y][x] = 0
elif this_image.getcolors() == rgba_1:
map[y][x] = 1
elif this_image.getcolors() == rgba_2:
map[y][x] = 2
elif this_image.getcolors() == rgba_3:
map[y][x] = 3
elif this_image.getcolors() == rgba_4:
map[y][x] = 4
elif this_image.getcolors() == rgba_5:
map[y][x] = 5
elif this_image.getcolors() == rgba_6:
map[y][x] = 6
elif this_image.getcolors() == rgba_8:
map[y][x] = 8
elif this_image.getcolors() == rgba_ed:
map[y][x] = -1
elif this_image.getcolors() == rgba_hongqi:
map[y][x] = -4
elif this_image.getcolors() == rgba_boom or this_image.getcolors() == rgba_boom_red:
global gameover
gameover = 1
break
#sys.exit(0)
else:
print("无法识别图像")
print("坐标")
print((y,x))
print("颜色")
print(this_image.getcolors())
sys.exit(0)
#print(map)5.扫雷算法
这里我采用的最基础的算法
1.首先点出一个点
2.扫描所有数字，如果周围空白+插旗==数字，则空白均有雷，右键点击空白插旗
3.扫描所有数字，如果周围插旗==数字，则空白均没有雷，左键点击空白
4.循环2、3，如果没有符合条件的，则随机点击一个白块
#插旗 def banner(): showmap() for y in range(blocks_y): for x in range(blocks_x): if 1 <= map[y][x] and map[y][x] <= 5: boom_number = map[y][x] block_white = 0 block_qi = 0 for yy in range(y-1,y+2): for xx in range(x-1,x+2): if 0 <= yy and 0 <= xx and yy < blocks_y and xx < blocks_x: if not (yy == y and xx == x):if map[yy][xx] == 0: block_white += 1 elif map[yy][xx] == -4: block_qi += 1if boom_number == block_white + block_qi:for yy in range(y - 1, y + 2): for xx in range(x - 1, x + 2): if 0 <= yy and 0 <= xx and yy < blocks_y and xx < blocks_x: if not (yy == y and xx == x): if map[yy][xx] == 0: win32api.SetCursorPos([left+xx*block_width, top+yy*block_height]) win32api.mouse_event(win32con.MOUSEEVENTF_RIGHTDOWN, 0, 0, 0, 0) win32api.mouse_event(win32con.MOUSEEVENTF_RIGHTUP, 0, 0, 0, 0) showmap() #点击白块 def dig(): showmap() iscluck = 0 for y in range(blocks_y): for x in range(blocks_x): if 1 <= map[y][x] and map[y][x] <= 5: boom_number = map[y][x] block_white = 0 block_qi = 0 for yy in range(y - 1, y + 2): for xx in range(x - 1, x + 2): if 0 <= yy and 0 <= xx and yy < blocks_y and xx < blocks_x: if not (yy == y and xx == x): if map[yy][xx] == 0: block_white += 1 elif map[yy][xx] == -4: block_qi += 1if boom_number == block_qi and block_white > 0:for yy in range(y - 1, y + 2): for xx in range(x - 1, x + 2): if 0 <= yy and 0 <= xx and yy < blocks_y and xx < blocks_x: if not(yy == y and xx == x): if map[yy][xx] == 0: win32api.SetCursorPos([left + xx * block_width, top + yy * block_height]) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTUP, 0, 0, 0, 0) iscluck = 1 if iscluck == 0: luck() #随机点击 def luck(): fl = 1 while(fl): random_x = random.randint(0, blocks_x - 1) random_y = random.randint(0, blocks_y - 1) if(map[random_y][random_x] == 0): win32api.SetCursorPos([left + random_x * block_width, top + random_y * block_height]) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTUP, 0, 0, 0, 0) fl = 0 def gogo(): win32api.SetCursorPos([left, top]) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTUP, 0, 0, 0, 0) showmap() global gameover while(1): if(gameover == 0): banner() banner() dig() else: gameover = 0 win32api.keybd_event(113, 0, 0, 0) win32api.SetCursorPos([left, top]) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTDOWN, 0, 0, 0, 0) win32api.mouse_event(win32con.MOUSEEVENTF_LEFTUP, 0, 0, 0, 0) showmap()
这个算法在初级和中级通过率都不错，但是在高级成功率惨不忍睹，主要是没有考虑逻辑组合以及白块是雷的概率问题，可以对这两个点进行改进，提高成功率
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