vb.net隨機數 vbs 随机数
vb.net产生随机数
方法名称:next();功能描述:返回一个0~2147483647之间的整数
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方法名称:next(i);功能描述:返回一个0~i之间的整数
方法名称:next(i,j);功能描述:返回一个i~j之间的整数
方法名称:Nextdouble();功能描述:返回一个0~1之间的随机小数
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使用方法:
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim rand = New System.Random()
MsgBox(rand.next().ToString())
End Sub
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产生N个不同数的话,我给你个我写的VB的代码,你稍微改下:
产生0-10的数:
Private Sub Command1_Click()
Randomize
Dim a(10) As Long
n = 10
For i = 0 To n
a(i) = Int(Rnd() * (n + 1))
For j = 0 To i - 1
If a(i) = a(j) Then
i = i - 1
Exit For
End If
Next
Next
For i = 0 To n
Print a(i)
Next
End Sub
VB.NET中怎么实现每单击一次按钮,文本框就多出现一个1-13的随机数字?
Dim n As Integer, b As Integer, a(13) As Integer
Private Sub Command1_Click()
If b 5 Then
b = b + 1
x = Int(n * Rnd()) + 1
Text1.Text = Text1.Text a(x) " "
a(x) = a(n)
n = n - 1
Else
Call Form_Load
End If
End Sub
Private Sub Form_Load()
Randomize
n = 13: b = 0
For i = 1 To 13
a(i) = i
Next i
Text1.Text = ""
End Sub
vb.net中产生三位正整数的随机数的程序写法
'项目:VB中产生在一定正整数范围内的不重复的随机数'作者:qq15495835Private Sub Command1_Click() Max = 100 '随机数上限值 Min = 1 '随机数下限值 Amount = 10 '产生号码数量(数量值应小于随机数上限值-随机数下限值)否则会产生死循环 ReDim a(Amount) Randomize For i = 0 To Amount a(i) = Int((Max - Min + 1) * Rnd + Min) For j = 0 To i If i j And a(i) = a(j) Then i = i - 1 Next Next Text1 = Join(a, vbCrLf)End Sub'请采纳参考!谢谢!
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