两矩阵相加java代码,两个矩阵的相加
java实现矩阵相加、相乘,判断是否上(下)三角矩阵、对称矩阵、相等的算法
class Matrix
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{
private int value[][]; //存储矩阵元素的二维数组
public Matrix(int m, int n) //构造m行n列的空矩阵
{
this.value=new int[m][n];
}
public Matrix(int n) //构造n行n列的空矩阵
{
this(n,n);
}
public Matrix()
{
this(10,10);
}
public Matrix(int mat[][]) //构造矩阵,由数组mat提供矩阵元素
{
this(mat.length,mat[0].length);
for (int i=0; imat.length; i++)
for (int j=0; jmat[i].length; j++)
this.value[i][j] = mat[i][j];
}
public int get(int i, int j) //获得矩阵第i行第j列的元素,O(1)
{
return value[i][j];
}
public void set(int i, int j, int k) //设置矩阵第i行第j列的元素,O(1)
{
value[i][j]=k;
}
public void add(Matrix b) //this和b两个矩阵相加,改变当前矩阵
{
for (int i=0; ithis.value.length; i++)
for (int j=0; jthis.value[i].length; j++)
this.value[i][j] += b.value[i][j];
}
public String toString() //行主序遍历,访问矩阵全部元素
{
String str="";
for (int i=0; ivalue.length; i++)
{
for (int j=0; jvalue[i].length; j++)
str += " "+value[i][j];
str += "\n";
}
return str;
}
public Matrix transpose() //矩阵的转置
{
Matrix trans = new Matrix(value[0].length, value.length);
for (int i=0; ithis.value.length; i++)
for (int j=0; jthis.value[i].length; j++)
trans.value[j][i]=this.value[i][j];
return trans;
}
//判断一个矩阵是否为上三角矩阵
public boolean isUpperTriangularMatrix() {
int i, j = 0;
int c = this.value[1][0];
for(i=1; ithis.value.length; i++)
for(j=0; ji; j++)
if(this.value[i][j] != c)
break;
if(i=this.value.length)
return true;
return false;
}
//判断一个矩阵是否为下三角矩阵
public boolean isLowerTriangularMatrix() {
int i, j = 0;
int c = this.value[0][1];
for(i=0; ithis.value.length-1; i++)
for(j=i+1; jthis.value[0].length; j++)
if(this.value[i][j] != c)
break;
if(i=this.value.length-1)
return true;
return false;
}
//判断一个矩阵是否为对称矩阵
public boolean isSymmetricMatrix () {
int i, j = 0;
for(i=1; ithis.value.length; i++)
for(j=0; ji; j++)
if(this.value[i][j] != this.value[j][i])
break;
if(i=this.value.length)
return true;
return false;
}
//比较两个矩阵是否相等
public boolean equals(Matrix b) {
int i, j = 0;
if(this.value.length != b.value.length || this.value[0].length != b.value[0].length)
return false;
for(i=0; ithis.value.length; i++)
for(j=0; jthis.value[0].length; j++)
if(this.value[i][j] != b.value[j][i])
break;
if(i=this.value.length)
return true;
return false;
}
//计算两个矩阵的乘积
public Matrix multiply(Matrix b){
int i, j, k;
int sum;
Matrix mtr;
if(this.value[0].length != b.value.length) {
return null;
}
mtr = new Matrix(this.value.length, b.value[0].length);
for(i=0; ithis.value.length; i++)
{
for(k=0; kb.value[0].length; k++){
for(sum=0,j=0; jthis.value[0].length; j++){
sum += this.value[i][j] * b.value[j][k];
mtr.value[i][k] = sum;
}
}
}
return mtr;
}
}
public class Test
{
public static void main(String args[])
{
int m1[][]={{1,2,3},{4,5,6}};
Matrix a=new Matrix(m1);
int m2[][]={{1,0,0},{0,1,0}};
Matrix b=new Matrix(m2);
System.out.print("Matrix a:\n"+a.toString());
System.out.print("Matrix b:\n"+b.toString());
a.add(b);
System.out.print("Matrix a:\n"+a.toString());
System.out.println("a的转置矩阵:\n"+a.transpose().toString());
int m3[][] = {{1,2,1},{0,3,1},{0,0,2}};
int m4[][] = {{1,0,0},{2,1,0},{3,2,1}};
int m5[][] = {{1,0,2},{0,1,0},{2,0,2}};
Matrix mtr1 = new Matrix(m3);
Matrix mtr2 = new Matrix(m4);
Matrix mtr3 = new Matrix(m5);
if(mtr1.isUpperTriangularMatrix())
System.out.println("上三角矩阵:\n" + mtr1.toString());
if(mtr2.isLowerTriangularMatrix())
System.out.println("下三角矩阵:\n" + mtr2.toString());
if(mtr3.isSymmetricMatrix())
System.out.println("对称矩阵:\n" + mtr3.toString());
System.out.println(mtr1.toString() + "\n乘以\n" + mtr2.toString() + "\n=\n");
Matrix tempM = mtr1.multiply(mtr2);
System.out.println(tempM.toString());
}
}
定义两个3*3的矩阵,用java数组编程并计算出两个矩阵相加和相乘的结果~
定义两3*3数组,分别输出矩阵之和跟相乘的结果,代码如下:
public class Problem {
public static void main(String[] args){
int arrayA[][]={{1,2,3},
{4,5,6},
{7,8,9}};
int arrayB[][]={{1,2,3},
{4,5,6},
{7,8,9}};
int arrayC[][] = new int[3][3];
int arrayD[][] = new int[3][3];
int i,j,k;
for (i = 0;i 3;i++){
for (j = 0; j 3; j++){
arrayC[i][j] = arrayA[i][j]+arrayB[i][j];
for (k = 0; k 3; k++){
arrayD[i][j] += arrayA[i][k]*arrayB[k][j];
}
System.out.print(arrayC[i][j]);
System.out.print(" ");
}
System.out.println();
}
System.out.println();
for (i = 0;i 3;i++){
for (j = 0; j 3; j++){
System.out.print(arrayD[i][j]);
System.out.print(" ");
}
System.out.println();
}
}
}
java中用二维数组实现两个矩阵相加
int[][] list1 = {{1, 2, 3}, {1, 2, 3}, {1, 2, 3}};
int[][] list2 = {{1, 2, 3}, {1, 2, 3}, {1, 2, 3}};
int[][] result = new int[3][3];
for(int i=0; ilist1.length; i++) {
for(int j=0; jlist1[i].length; j++) {
result[i][j] = list1[i][j] + list2[i][j];
}
}
这里的前提是两个矩阵大小一样
java题: 自己定义两个4*4阶矩阵,求两个矩阵的和、差。
看来楼主还是新手,我把代码尽可能的给你写的详细了点,主要还是记住,数组的操作就用for循环,几维的数组就嵌套几个循环就行,比如本例中的是二维数组,所以用两个for循环进行数组的输入和数组的输出就行了。加油,多多练习就ok。代码如下:
#includestdio.h
void main()
{
int i,j,a[4][5]={0},b[4][5]={0},c[4][5]={0};
printf("请输入a矩阵的各个元素:\n");
for(i=0;i4;i++)
for(j=0;j5;j++)
scanf("%d",a[i][j]);
printf("请输入b矩阵的各个元素:\n");
for(i=0;i4;i++)
for(j=0;j5;j++)
scanf("%d",b[i][j]);
printf("您输入的a矩阵是:\n");
for(i=0;i4;i++)
{
for(j=0;j5;j++)
printf("%d ",a[i][j]);
printf("\n");
}
printf("\n");
printf("\n");
printf("您输入的a矩阵是:\n");
for(i=0;i4;i++)
{
for(j=0;j5;j++)
printf("%d ",b[i][j]);
printf("\n");
}
for(i=0;i4;i++)
for(j=0;j5;j++)
c[i][j]=a[i][j]+b[i][j];
printf("两个矩阵相加的结果为:\n");
printf("\n");
printf("\n");
for(i=0;i4;i++)
{
for(j=0;j5;j++)
printf("%d ",c[i][j]);
printf("\n");
}
}
用JAVA编写一个 两个2*2的矩阵求和,刚开始学JAVA 很多地方不是很懂。麻烦讲一下。
public static void main(String[] args)
{
int[][] a = {{1,2,3},{4,5,6},{7,8,9}};
int[][] b = {{1,2,3},{4,5,6},{7,8,9}};
int[][] c = new int[3][3];
for(int i = 0;i 3;i++)
{
for(int j = 0;j 3;j++)
{
c[i][j] = a[i][j] + b[i][j];
}
}
for(int i = 0;i 3;i++)
{
for(int j = 0;j 3;j++)
{
System.out.print(c[i][j] + " ");
}
System.out.println();
}
}
用java编程:实现两个矩阵相加.
封装性不用担心,java正是以其良好的封装性著称。
小可献丑了:
//没有仔细调试,按照提示输入数据
//每一行(Row)数据用空格隔开,结束后回车
import java.io.*;
import java.util.*;
public class Arrtest{
public static void main(String args[]){
try{
System.out.print("set the row of the arr:\n");
BufferedReader in=new BufferedReader(
new InputStreamReader(System.in));
String row=in.readLine();
System.out.print("set the line of the arr:\n");
BufferedReader in2=new BufferedReader(
new InputStreamReader(System.in));
String line=in2.readLine();
int R=Integer.parseInt(row);
int L=Integer.parseInt(line);
Arr arr=new Arr();
System.out.print("Great the first arr:\n");
double arr1[][]=arr.greatArr(R,L);
System.out.print("Great the second arr:\n");
double arr2[][]=arr.greatArr(R,L);
arr.showArr(arr.addArr(arr1,arr2,R,L),R,L);
}catch(Exception e){e.getMessage(); }
}
}
class Arr {
double[][] greatArr(int row,int line){
double arr[][]=new double[row][line];
for(int i=0;irow;i++){
try{
System.out.print("input the row("+(i+1)+") numbers:\n");
BufferedReader in=new BufferedReader(
new InputStreamReader(System.in));
String s=in.readLine();
StringTokenizer s_part=new StringTokenizer(s," ");
for(int j=0;jline;j++){
arr[i][j]=Double.parseDouble(s_part.nextToken());
}
}catch(Exception e){e.getMessage(); }
}
return arr;
}
double[][] addArr(double[][] arr1,double[][] arr2,int row,int line){
for(int i=0;irow;i++){
for(int j=0;jline;j++){
arr1[i][j]=arr1[i][j]+arr2[i][j];
}
}
return arr1;
}
void showArr(double[][] arr,int row,int line){
System.out.print("the result:\r\n");
for(int i=0;irow;i++){
for(int j=0;jline;j++){
System.out.print(arr[i][j]+" ");
}
System.out.print("\r\n");
}
}
}
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