ShardingJDBC分表怎么配置
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分表配置
由于的单库分表,所以只配置一个数据源就可以了
#配置数据源 spring.shardingsphere.datasource.names=test0 #test0 spring.shardingsphere.datasource.test0.type=com.zaxxer.hikari.HikariDataSource spring.shardingsphere.datasource.test0.driver-class-name=com.MySQL.cj.jdbc.Driver spring.shardingsphere.datasource.test0.jdbcUrl=jdbc:mysql://127.0.0.1:3306/test0 spring.shardingsphere.datasource.test0.username=devadmin spring.shardingsphere.datasource.test0.password=
设置绑定表
# 设置绑定表 spring.shardingsphere.sharding.binding-tables[0]=health_record,health_task
设置分表的策略
这里根据 record_id 奇偶来分表的。分为 health_record0,health_record1 和 health_task0,health_task1
# health_record spring.shardingsphere.sharding.tables.health_record.actual-data-nodes=test0.health_record$->{0..1} spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.algorithm-expression=health_record$->{record_id % 2} spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.sharding-column=record_id spring.shardingsphere.sharding.tables.health_record.key-generator.column=record_id spring.shardingsphere.sharding.tables.health_record.key-generator.type=SNOWFLAKE # health_task spring.shardingsphere.sharding.tables.health_task.actual-data-nodes=test0.health_task$->{0..1} spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.algorithm-expression=health_task$->{record_id %2} spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.sharding-column=record_id spring.shardingsphere.sharding.tables.health_task.key-generator.column=task_id spring.shardingsphere.sharding.tables.health_task.key-generator.type=SNOWFLAKE
完整配置
server.port=8080 #打印sql spring.shardingsphere.props.sql.show=true #配置数据源 spring.shardingsphere.datasource.names=test0 #test0 spring.shardingsphere.datasource.test0.type=com.zaxxer.hikari.HikariDataSource spring.shardingsphere.datasource.test0.driver-class-name=com.mysql.cj.jdbc.Driver spring.shardingsphere.datasource.test0.jdbcUrl=jdbc:mysql://127.0.0.1:3306/test0 spring.shardingsphere.datasource.test0.username=devadmin spring.shardingsphere.datasource.test0.password= # 设置绑定表 spring.shardingsphere.sharding.binding-tables[0]=health_record,health_task # health_record spring.shardingsphere.sharding.tables.health_record.actual-data-nodes=test0.health_record$->{0..1} spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.algorithm-expression=health_record$->{record_id % 2} spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.sharding-column=record_id spring.shardingsphere.sharding.tables.health_record.key-generator.column=record_id spring.shardingsphere.sharding.tables.health_record.key-generator.type=SNOWFLAKE # health_task spring.shardingsphere.sharding.tables.health_task.actual-data-nodes=test0.health_task$->{0..1} spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.algorithm-expression=health_task$->{record_id %2} spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.sharding-column=record_id spring.shardingsphere.sharding.tables.health_task.key-generator.column=task_id spring.shardingsphere.sharding.tables.health_task.key-generator.type=SNOWFLAKE
数据库如下
health_level 数据如下
user数据如下
health_record0,health_record1
health_record0 中 record_id 都是偶数 ,health_record1 都是奇数
health_task0,health_task1
health_task0 中 record_id 都是偶数 ,health_task1 都是奇数
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文章名称:ShardingJDBC分表怎么配置
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