怎么在python中使用pygame实现一个2048游戏-创新互联
这期内容当中小编将会给大家带来有关怎么在python中使用pygame实现一个2048游戏，文章内容丰富且以专业的角度为大家分析和叙述，阅读完这篇文章希望大家可以有所收获。
代码
import random
import sys
import pygame
from pygame.locals import *
PIXEL = 150
SCORE_PIXEL = 100
SIZE = 4
# 地图的类
class Map:
def __init__(self, size):
self.size = size
self.score = 0
self.map = [[0 for i in range(size)] for i in range(size)]
self.add()
self.add()
# 新增2或4，有1/4概率产生4
def add(self):
while True:
p = random.randint(0, self.size * self.size - 1)
if self.map[p / self.size][p % self.size] == 0:
x = random.randint(0, 3) > 0 and 2 or 4
self.map[p / self.size][p % self.size] = x
self.score += x
break
# 地图向左靠拢，其他方向的靠拢可以通过适当旋转实现，返回地图是否更新
def adjust(self):
changed = False
for a in self.map:
b = []
last = 0
for v in a:
if v != 0:
if v == last:
b.append(b.pop() << 1)
last = 0
else:
b.append(v)
last = v
b += [0] * (self.size - len(b))
for i in range(self.size):
if a[i] != b[i]:
changed = True
a[ : ] = b
return changed
# 逆时针旋转地图90度
def rotate90(self):
self.map = [[self.map[c][r] for c in range(self.size)] for r in reversed(range(self.size))]
# 判断游戏结束
def over(self):
for r in range(self.size):
for c in range(self.size):
if self.map[r][c] == 0:
return False
for r in range(self.size):
for c in range(self.size - 1):
if self.map[r][c] == self.map[r][c + 1]:
return False
for r in range(self.size - 1):
for c in range(self.size):
if self.map[r][c] == self.map[r + 1][c]:
return False
return True
def moveUp(self):
self.rotate90()
if self.adjust():
self.add()
self.rotate90()
self.rotate90()
self.rotate90()
def moveRight(self):
self.rotate90()
self.rotate90()
if self.adjust():
self.add()
self.rotate90()
self.rotate90()
def moveDown(self):
self.rotate90()
self.rotate90()
self.rotate90()
if self.adjust():
self.add()
self.rotate90()
def moveLeft(self):
if self.adjust():
self.add()
# 更新屏幕
def show(map):
for i in range(SIZE):
for j in range(SIZE):
# 背景颜色块
screen.blit(map.map[i][j] == 0 and block[(i + j) % 2] or block[2 + (i + j) % 2], (PIXEL * j, PIXEL * i))
# 数值显示
if map.map[i][j] != 0:
map_text = map_font.render(str(map.map[i][j]), True, (106, 90, 205))
text_rect = map_text.get_rect()
text_rect.center = (PIXEL * j + PIXEL / 2, PIXEL * i + PIXEL / 2)
screen.blit(map_text, text_rect)
# 分数显示
screen.blit(score_block, (0, PIXEL * SIZE))
score_text = score_font.render((map.over() and "Game over with score " or "Score: ") + str(map.score), True, (106, 90, 205))
score_rect = score_text.get_rect()
score_rect.center = (PIXEL * SIZE / 2, PIXEL * SIZE + SCORE_PIXEL / 2)
screen.blit(score_text, score_rect)
pygame.display.update()
map = Map(SIZE)
pygame.init()
screen = pygame.display.set_mode((PIXEL * SIZE, PIXEL * SIZE + SCORE_PIXEL))
pygame.display.set_caption("2048")
block = [pygame.Surface((PIXEL, PIXEL)) for i in range(4)]
# 设置颜色
block[0].fill((152, 251, 152))
block[1].fill((240, 255, 255))
block[2].fill((0, 255, 127))
block[3].fill((225, 255, 255))
score_block = pygame.Surface((PIXEL * SIZE, SCORE_PIXEL))
score_block.fill((245, 245, 245))
# 设置字体
map_font = pygame.font.Font(None, PIXEL * 2 / 3)
score_font = pygame.font.Font(None, SCORE_PIXEL * 2 / 3)
clock = pygame.time.Clock()
show(map)
while not map.over():
# 12为实验参数
clock.tick(12)
for event in pygame.event.get():
if event.type == QUIT:
sys.exit()
# 接收玩家操作
pressed_keys = pygame.key.get_pressed()
if pressed_keys[K_w] or pressed_keys[K_UP]:
map.moveUp()
elif pressed_keys[K_s] or pressed_keys[K_DOWN]:
map.moveDown()
elif pressed_keys[K_a] or pressed_keys[K_LEFT]:
map.moveLeft()
elif pressed_keys[K_d] or pressed_keys[K_RIGHT]:
map.moveRight()
show(map)
# 游戏结束
pygame.time.delay(3000)上述就是小编为大家分享的怎么在python中使用pygame实现一个2048游戏了，如果刚好有类似的疑惑，不妨参照上述分析进行理解。如果想知道更多相关知识，欢迎关注创新互联行业资讯频道。
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