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Android应用中获取设备唯一ID的方法有哪些

本篇文章为大家展示了Android应用中获取设备唯一ID的方法有哪些，内容简明扼要并且容易理解，绝对能使你眼前一亮，通过这篇文章的详细介绍希望你能有所收获。

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先来看看几种比较单一的方式：

IMEI

方式：TelephonyManager.getDeviceId():

问题

  1. 范围：只能支持拥有通话功能的设备，对于平板不可以。
  2. 持久性：返厂，数据擦除的时候不彻底，保留了原来的标识。
  3. 权限：需要权限：Android.permission.READ_PHONE_STATE
  4. bug: 有些厂家的实现有bug，返回一些不可用的数据

 Mac地址

ACCESS_WIFI_STATE权限

有些设备没有WiFi，或者蓝牙，就不可以，如果WiFi没有打开，硬件也不会返回Mac地址，不建议使用

ANDROID_ID
2.2（Froyo，8）版本系统会不可信，来自主要生产厂商的主流手机，至少有一个普遍发现的bug，这些有问题的手机相同的ANDROID_ID: 9774d56d682e549c

但是如果返厂的手机，或者被root的手机，可能会变

Serial Number

从Android 2.3 (“Gingerbread”)开始可用，可以通过android.os.Build.SERIAL获取，对于没有通话功能的设备，它会返回一个唯一的device ID，

以下几个是stackoverflow上评论较多的几个，没贴完，还有其他，综合的，用到以上的部分方式：

地址：http://stackoverflow.com/questions/2785485/is-there-a-unique-android-device-id

有兴趣的朋友可以再仔细看看

支持率比较高的（支持票数157）：androidID --> 剔除2.2版本（API 8）中有问题的手机，使用UUID替代

import android.content.Context; 
import android.content.SharedPreferences; 
import android.provider.Settings.Secure; 
import android.telephony.TelephonyManager; 
 
import java.io.UnsupportedEncodingException; 
import java.util.UUID; 
 
public class DeviceUuidFactory { 
 
  protected static final String PREFS_FILE = "device_id.xml"; 
  protected static final String PREFS_DEVICE_ID = "device_id"; 
  protected static volatile UUID uuid; 
 
  public DeviceUuidFactory(Context context) { 
    if (uuid == null) { 
      synchronized (DeviceUuidFactory.class) { 
        if (uuid == null) { 
          final SharedPreferences prefs = context 
              .getSharedPreferences(PREFS_FILE, 0); 
          final String id = prefs.getString(PREFS_DEVICE_ID, null); 
          if (id != null) { 
            // Use the ids previously computed and stored in the 
            // prefs file 
            uuid = UUID.fromString(id); 
          } else { 
            final String androidId = Secure.getString( 
              context.getContentResolver(), Secure.ANDROID_ID); 
            // Use the Android ID unless it's broken, in which case 
            // fallback on deviceId, 
            // unless it's not available, then fallback on a random 
            // number which we store to a prefs file 
            try { 
              if (!"9774d56d682e549c".equals(androidId)) { 
                uuid = UUID.nameUUIDFromBytes(androidId 
                    .getBytes("utf8")); 
              } else { 
                final String deviceId = ((TelephonyManager)  
                    context.getSystemService( 
                      Context.TELEPHONY_SERVICE) 
                      .getDeviceId(); 
                uuid = deviceId != null ? UUID 
                    .nameUUIDFromBytes(deviceId 
                        .getBytes("utf8")) : UUID 
                    .randomUUID(); 
              } 
            } catch (UnsupportedEncodingException e) { 
              throw new RuntimeException(e); 
            } 
            // Write the value out to the prefs file 
            prefs.edit() 
                .putString(PREFS_DEVICE_ID, uuid.toString()) 
                .commit(); 
          } 
        } 
      } 
    } 
  } 
 
  /** 
   * Returns a unique UUID for the current android device. As with all UUIDs, 
   * this unique ID is "very highly likely" to be unique across all Android 
   * devices. Much more so than ANDROID_ID is. 
   * 
   * The UUID is generated by using ANDROID_ID as the base key if appropriate, 
   * falling back on TelephonyManager.getDeviceID() if ANDROID_ID is known to 
   * be incorrect, and finally falling back on a random UUID that's persisted 
   * to SharedPreferences if getDeviceID() does not return a usable value. 
   * 
   * In some rare circumstances, this ID may change. In particular, if the 
   * device is factory reset a new device ID may be generated. In addition, if 
   * a user upgrades their phone from certain buggy implementations of Android 
   * 2.2 to a newer, non-buggy version of Android, the device ID may change. 
   * Or, if a user uninstalls your app on a device that has neither a proper 
   * Android ID nor a Device ID, this ID may change on reinstallation. 
   * 
   * Note that if the code falls back on using TelephonyManager.getDeviceId(), 
   * the resulting ID will NOT change after a factory reset. Something to be 
   * aware of. 
   * 
   * Works around a bug in Android 2.2 for many devices when using ANDROID_ID 
   * directly. 
   * 
   * @see http://code.google.com/p/android/issues/detail?id=10603 
   * 
   * @return a UUID that may be used to uniquely identify your device for most 
   *     purposes. 
   */ 
  public UUID getDeviceUuid() { 
    return uuid; 
  } 
}

根据版本进行判断的方式：Serial序列号-->UUID （支持数31）

通过Serial 即可，在覆盖率上，你已经成功的获得了98.4%的用户，剩下的1.6%的用户系统是在9 以下的。

通过AndroidID获取，前面已经说过，在8上，有些商家的手机会有一些bug，返回相同的AndroidID，如果Serial和AndroidID都不行

/** 
 * Return pseudo unique ID 
 * @return ID 
 */ 
public static String getUniquePsuedoID() 
{ 
  // If all else fails, if the user does have lower than API 9 (lower 
  // than Gingerbread), has reset their phone or 'Secure.ANDROID_ID' 
  // returns 'null', then simply the ID returned will be solely based 
  // off their Android device information. This is where the collisions 
  // can happen. 
  // Thanks http://www.pocketmagic.net/?p=1662! 
  // Try not to use DISPLAY, HOST or ID - these items could change. 
  // If there are collisions, there will be overlapping data 
  String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10); 
 
  // Thanks to @Roman SL! 
  // http://stackoverflow.com/a/4789483/950427 
  // Only devices with API >= 9 have android.os.Build.SERIAL 
  // http://developer.android.com/reference/android/os/Build.html#SERIAL 
  // If a user upgrades software or roots their phone, there will be a duplicate entry 
  String serial = null; 
  try 
  { 
    serial = android.os.Build.class.getField("SERIAL").get(null).toString(); 
 
    // Go ahead and return the serial for api => 9 
    return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString(); 
  } 
  catch (Exception e) 
  { 
    // String needs to be initialized 
    serial = "serial"; // some value 
  } 
 
  // Thanks @Joe! 
  // http://stackoverflow.com/a/2853253/950427 
  // Finally, combine the values we have found by using the UUID class to create a unique identifier 
  return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString(); 
}

不用READ_PHONE_STATE权限直接获取ROM信息的方式：（支持率较低 16）

String m_szDevIDShort = "35" + //we make this look like a valid IMEI 
      Build.BOARD.length()%10+ Build.BRAND.length()%10 + 
      Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 + 
      Build.DISPLAY.length()%10 + Build.HOST.length()%10 + 
      Build.ID.length()%10 + Build.MANUFACTURER.length()%10 + 
      Build.MODEL.length()%10 + Build.PRODUCT.length()%10 + 
      Build.TAGS.length()%10 + Build.TYPE.length()%10 + 
      Build.USER.length()%10 ; //13 digits

最后贴上自己在项目中用的：

public static String getDeviceId(Context context) { 
    String deviceId = ""; 
    if (deviceId != null && !"".equals(deviceId)) { 
     return deviceId; 
   } 
    if (deviceId == null || "".equals(deviceId)) { 
      try { 
        deviceId = getLocalMac(context).replace(":", ""); 
      } catch (Exception e) { 
        e.printStackTrace(); 
      } 
    } 
    if (deviceId == null || "".equals(deviceId)) { 
      try { 
        deviceId = getAndroidId(context); 
      } catch (Exception e) { 
        e.printStackTrace(); 
      } 
    } 
    if (deviceId == null || "".equals(deviceId)) { 
       
      if (deviceId == null || "".equals(deviceId)) { 
        UUID uuid = UUID.randomUUID(); 
        deviceId = uuid.toString().replace("-", ""); 
        writeDeviceID(deviceId); 
      } 
    } 
    return deviceId; 
  } 
// IMEI码 
  private static String getIMIEStatus(Context context) { 
    TelephonyManager tm = (TelephonyManager) context 
        .getSystemService(Context.TELEPHONY_SERVICE); 
    String deviceId = tm.getDeviceId(); 
    return deviceId; 
  } 
 
  // Mac地址 
  private static String getLocalMac(Context context) { 
    WifiManager wifi = (WifiManager) context 
        .getSystemService(Context.WIFI_SERVICE); 
    WifiInfo info = wifi.getConnectionInfo(); 
    return info.getMacAddress(); 
  } 
 
  // Android Id 
  private static String getAndroidId(Context context) { 
    String androidId = Settings.Secure.getString( 
        context.getContentResolver(), Settings.Secure.ANDROID_ID); 
    return androidId; 
  } 
 
  public static void saveDeviceID(String str) { 
    try { 
      FileOutputStream fos = new FileOutputStream(file); 
      Writer out = new OutputStreamWriter(fos, "UTF-8"); 
      out.write(str); 
      out.close(); 
    } catch (IOException e) { 
      e.printStackTrace(); 
    } 
  } 
 
  public static String readDeviceID() { 
    StringBuffer buffer = new StringBuffer(); 
    try { 
      FileInputStream fis = new FileInputStream(file); 
      InputStreamReader isr = new InputStreamReader(fis, "UTF-8"); 
      Reader in = new BufferedReader(isr); 
      int i; 
      while ((i = in.read()) > -1) { 
        buffer.append((char) i); 
      } 
      in.close(); 
      return buffer.toString(); 
    } catch (IOException e) { 
      e.printStackTrace(); 
      return null; 
    } 
  }

上述内容就是Android应用中获取设备唯一ID的方法有哪些，你们学到知识或技能了吗？如果还想学到更多技能或者丰富自己的知识储备，欢迎关注创新互联行业资讯频道。


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